Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 112

Answer

$(x+y)^{2}(x+y-10)(x+y+10)$

Work Step by Step

$(x+y)^{4}-100(x+y)^{2}=\quad$... factor out $(x+y)^{2}$ $=(x+y)^{2}((x+y)^{2}-100)$ ... the brackets hold a difference of squares $=(x-y)^{2}[(x+y)-10]\cdot[(x+y)+10]$ $=(x+y)^{2}(x+y-10)(x+y+10)$
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