Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 95

Answer

$\displaystyle \frac{4(1+2x)}{x^{2/3}}$

Work Step by Step

$4x^{-2/3}+8x^{1/3}=4x^{-2/3}+4\cdot 2\cdot x^{-\frac{2}{3}+1}$ $=4x^{-2/3}+4\cdot 2\cdot x^{-2/3}\cdot x \qquad$... factor out $4x^{-\frac{2}{3}}$ $=4x^{-2/3}(1+2x)\qquad $... $a^{-n}=\displaystyle \frac{1}{a^{n}}$ $=\displaystyle \frac{4(1+2x)}{x^{2/3}}$
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