Answer
$9x(x-1)(x+1)$
Work Step by Step
Factor out $9x$ to obtain:
$=9x(x^2-1)
\\=x(x^2-1^2)$
Factor the difference of two squares using the formula $a^2-b^2=(a-b)(a+b)$ where $a=x$ and $b=1$ to obtain:
$=9x(x-1)(x+1)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 76
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