Answer
$3y^2(4y+1)(4y-1)$
Work Step by Step
$ 48y^4 - 3y^2$
factor out GCF...
$3y^2(16y^2-1)$
Recall that $a^2−b^2=(a+b)(a−b)$. We use this to simplify the expression:
$3y^2(16y^2-1)=3y^2(4y+1)(4y-1)$.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 84
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