Answer
$(x+2)(x-2)(x+2)$
Work Step by Step
Regroup to obtain:
$=(x^3+2x^2) + (-4x-8)$
Factor out $x^2$ in the first group and $-4$ in the second to obtain:
$=x^2(x+2) + (-4)(x+2)
\\=x^2(x+2) - 4(x+2)$
Factor out the GCF of $x+2$ to obtain:
$=(x+2)(x^2-4)
\\=(x+2)(x^2-2^2)$
Factor the difference of two squares using the formula $a^2-b^2=(a-b)(a+b)$ to obtain:
$=(x+2)(x-2)(x+2)$
