Answer
$(x-3y^{2})(2x-3y^{2}) $
Work Step by Step
$2x^{2}-7xy^{2}+3y^{4}=$
Treat as a trinomial of the form $ax^{2}+bx+c,$
$=2x^{2}-7y^{2}\cdot x+3y^{4}$
we search for factors of $ac=6y^{2}$ whose sum is $b=-7y^{2}$
and we find $-6y^{2}$ and $-y^{2}$
rewrite bx and factor in pairs
$=2x^{2}-6y^{2}\cdot x-y^{2}\cdot x+3y^{4}$
$=2x(x-3y^{2})-y^{2}(x-3y^{2})$
$=(x-3y^{2})(2x-3y^{2}) $
