Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 66

Answer

$5x(x-3)(x+3)$

Work Step by Step

Factor out the GCF of $5x$ to obtain: $=5x(x^2-9) \\=5x(x^2-3^2)$ Factor the difference of two squares using the formula $a^2-b^2=(a-b)(a+b)$ to obtain: $=5x(x-3)(x+3)$
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