Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 14

Answer

Solution set = $\{-19\}$

Work Step by Step

Multiply both sides with the LCD, $24$ $ 24 \left[5+\displaystyle \frac{x-2}{3}\right]=24 \left[ \dfrac{x+3}{8} \right]\quad$ ... distribute and simplify $ 120+4(x-2)=3(x+3)\quad$ ... distribute and simplify $120+8x-16=3x+9$ $ 8x+104=3x+9\quad$ ... add $-3x-104$ to both sides $8x-3x=9-104$ $5x=-95$ $x=-19$ Solution set = $\{-19\}$
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