Answer
$x=\frac{-11\pm\sqrt {33}}{4}$
Work Step by Step
$ (2x + 3)(x + 4) = 1$
$2x^2+11x+12=1$
$2x^2+11x+11=0$
$x=\frac{-11\pm\sqrt {{11}^2-4*2*11}}{2*2}=\frac{-11\pm\sqrt {121-88}}{4}=\frac{-11\pm\sqrt {33}}{4}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 99
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