Answer
$x=\frac{-3\pm\sqrt {17}}{4}$
Work Step by Step
$2x^2 + 3x = 1$
$2x^2 + 3x -1=0$
$x=\frac{-3\pm\sqrt {3^2-4*2*(-1)}}{2*2}=\frac{-3\pm\sqrt {9+8}}{4}=\frac{-3\pm\sqrt {17}}{4}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 98
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