Answer
$\left\{4-\sqrt5, 4+\sqrt5\right\}$
Work Step by Step
Divide 3 on both sides of the equation to obtain:
$(x-4)^2=5$
Take the square root of both sides to obtain:
$x-4 = \pm \sqrt{5}$
Add 4 on both sides of the equation to obtain:
$x=4 \pm \sqrt{5}$
Thus, the solution set of the given equation is $\left\{4-\sqrt5, 4+\sqrt5\right\}$.
