Answer
$\left\{-4, 4\right\}$
Work Step by Step
Add 1 on both sides of the equation to obtain:
$3x^2 = 48$
Divide 3 on both sides of the equation to obtain:
$x^2=16$
Take the square root of both sides to obtain:
$x = \pm \sqrt{16}
\\x=\pm \sqrt{4^2}
\\x = \pm 4$
Thus, the solution set of the given equation is $\left\{-4, 4\right\}$.
