Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 18

Answer

(x+8)(x−16)

Work Step by Step

We first multiply the entire expression by 8 to get rid of fractions. Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $-128$ and add to get $-8$. Thus, we find that the solution is: $$(x+8)(x−16)$$
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