Answer
{$1-2\sqrt 2, 1+2\sqrt 2$}
Work Step by Step
$7+2x-x^2=0$
$x^2-2x=7$
$x^2-2x+1=8$
$(x-1)^2=8$
$x-1=+2\sqrt 2, -2\sqrt 2$
$x=1+2\sqrt 2, 1-2\sqrt 2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 39
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