Answer
{-1, 3}
Work Step by Step
$x^2-2x-3 = x^2+x - 3x -3 = x(x+1)-3(x+1)=(x-3)(x+1)=0$
Either x-3=0 that gives x=3
or x+1=0 that gives x=-1
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 34
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