Answer
$\frac{1}{(x-1)^2+2^2}$
Work Step by Step
$\frac{1}{x^2-2x+5}=\frac{1}{x^2-2(1)x+1^2-1^2+5}=\frac{1}{(x-1)^2+4}=\frac{1}{(x-1)^2+2^2}$
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