Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 65

Answer

No real solutions

Work Step by Step

Quadratic Equation : $\frac{1}{3}x^2-5x+25=0$ Use discriminant to determine the number of real solutions. Discriminant = $(-5)^2-4(\frac{1}{3})(25)=\frac{-25}{3}$ which is less than zero, hence no real solutions.
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