Answer
$\frac{1}{(2x+1)^2+8}$
Work Step by Step
$\frac{1}{4x^2+4x+9}=\frac{1}{4x^2+4x+1+8}=$$\frac{1}{(2x+1)^2+8}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 47
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