Answer
$\frac{1}{\sqrt {25-(x+3)^2}}$
Work Step by Step
$\frac{1}{\sqrt {16-6x-x^2}}=\frac{1}{\sqrt {25-(x^2+6x+9)}}=$$\frac{1}{\sqrt {25-(x+3)^2}}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 50
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