Answer
Solutions:
$x=-2+\sqrt 2$
$x=-2-\sqrt 2$
Work Step by Step
$x^2+4x+2=0$
$x^2+2(2)x+2^2+2=2^2$
$(x+2)^2=4-2$
$(x+2)^2=2$
$x+2=±\sqrt 2$
$x=-2+\sqrt 2$ or
$x=-2-\sqrt 2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 35
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