Answer
No real solutions
Work Step by Step
$-x^2+x-1=0$
$x^2-x+1=0$
$x^2-x+\frac{1}{4}=-1+\frac{1}{4}$
$(x-\frac{1}{2})^2=-\frac{3}{4}$
A square of a real value cannot be negative. Hence no real soultions.
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 40
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