Answer
{$\frac{1-\sqrt 2}{2}, \frac{1+\sqrt 2}{2}$}
Work Step by Step
$4x^2-4x=1$
$4x^2-4x+1=2$
$(2x-1)^2=2$
2x-1=$+\sqrt 2 or -\sqrt 2$
2x=$1+\sqrt 2 or 1-\sqrt 2$
x={$\frac{1-\sqrt 2}{2}, \frac{1+\sqrt 2}{2}$}
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