Answer
$(6x+7)(6x-7)$
Work Step by Step
If $a$ and $b$ are real numbers, we know that $a^{2}-b^{2}=(a+b)(a-b)$. In words, the difference of the squares of two terms factors as a product of a sum and a difference of those terms.
Therefore, we know that $36x^{2}-49=(6x+7)(6x-7)$. In this case, $a=6x$ and $b=7$.
