Answer
$(3x-1)^{2}$
Work Step by Step
If a and b are real numbers, we know that $a^{2}-2ab+b^{2}=(a-b)^{2}$.
Therefore, we know that $9x^{2}-6x+1=(3x-1)^{2}$. In this case, $a=3x$ and $b=1$.
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