Answer
$2(x+7)(x-8)$
Work Step by Step
$2x^{2}-2x-112$
Factor out common factor 2 from the expression.
$2(x^{2}-x-56)$
Since the last term of $(x^{2}-x-56)$ is -56. We need to find two factors of -56 that have a sum of -1.
7 and -8 are factors of -56. Also, $7\times-8=-56$ and $7-8=-1$
Therefore, $2(x^{2}-x-56)$ can be written as
$=2(x^{2}+7x-8x-56)$
Group the terms.
$=2((x^{2}+7x)+(-8x-56))$
Factor out common factors.
$=2(x(x+7)-8(x+7))$
Factor out common factor (x+7).
$=2((x+7)(x-8))$
