College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 74: 57

Answer

$(x+3)(x^{2}-3x+9)$

Work Step by Step

If a and b are real numbers, we know that $a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2)}$. Therefore, we know that $x^{3}+27=(x+3)(x^{2}-x\times3+3^{2})=(x+3)(x^{2}-3x+9)$. In this case, $a=x$ and $b=3$.
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