Answer
$(x-3)(x^{2}+3x+9)$
Work Step by Step
If $a$ and $b$ are real numbers, we know that $a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})$.
Therefore, we know that $x^{3}-27=(x-3)(x^{2}+x\times3+3^{2})=(x-3)(x^{2}+3x+9)$. In this case, $a=x$ and $b=3$.
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