Answer
$(x^{2}+4x+16)$
Work Step by Step
If $a$ and $b$ are real numbers, we know that $a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})$.
Therefore, we know that $x^{3}-64=(x-4)(x^{2}+x\times4+4^{2})=(x-4)(x^{2}+4x+16)$. In this case, $a=x$ and $b=4$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 74: 59
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
