Answer
$(x+4)(x^{2}-4x+16)$
Work Step by Step
If a and b are real numbers, we know that $a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2)}$.
Therefore, we know that $x^{3}+64=(x+4)(x^{2}-x\times4+4^{2})=(x+4)(x^{2}-4x+16)$. In this case, $a=x$ and $b=4$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 74: 58
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