Answer
$(x+1)^{2}$
Work Step by Step
If $a$ and $b$ are real numbers, we know that $a^{2}+2ab+b^{2}=(a+b)^{2}$.
Therefore, we know that $x^{2}+2x+1=(x+1)^{2}$. In this case, $a=x$ and $b=1$.
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