Answer
$(8x-1)^{2}$
Work Step by Step
If a and b are real numbers, we know that $a^{2}-2ab+b^{2}=(a-b)^{2}$.
Therefore, we know that $64x^{2}-16x+1=(8x-1)^{2}$. In this case, $a=8x$ and $b=1$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 74: 56
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