Answer
(6p + 5q)(36$p^2$ + 25$q^2$ - 30pq)
Work Step by Step
216$p^3$ + 125$q^3$
= $(6p)^3$ + $(5q)^3$
Now, $a^3$ + $b^3$ = (a+b)($a^2$ + $b^2$ - ab)
and a = 6p , b = 5q
Which implies,
= (6p + 5q)(36$p^2$ + 25$q^2$ - 30pq)
which is the answer
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 108
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