Answer
$x\left( x^{2}-12x+16\right) $
Work Step by Step
$\left( x-4\right) ^{3}+64=\left( x-4\right) ^{3}+4^{3}=\left( \left( x-4\right) +4\right) \left( \left( x-4\right) ^{2}-4\times \left( x+4\right) +4^{2}\right) =x\left( x^{2}-12x+16\right) $
