Answer
$(2m^{2}+9)(5m^{2}-1)$
Work Step by Step
Substitute $u=m^{2}.$
$10m^{4}+43m^{2}-9=10u^{2}+43u-9=...$
When factoring $ax^{2}+bx+c$,
we search for factors of $ac=-90$ whose sum is $b=43,$
Here, these factors are $-2$ and $+45$
$...=10u^{2}+45u-2u-9$
$=5u(2u+9)-(2u+9)$
$=(2u+9)(5u-1)$
... bring back $m$
$=(2m^{2}+9)(5m^{2}-1)$
