Answer
$(3p+2k)(-2p+3k)$
or
$(2k+3p)(3k-2p)$
Work Step by Step
When factoring $ax^{2}+bx+c$, we search for factors of $ac$ whose sum is $b,$
and, if we find them, we rewrite $bx$ and proceed to factor in groups.
Here, factors of $(6)\times(-6)=-36$ that add to $+5$ are ....$+9$ and $-4.$
$6k^{2}+5kp-6p^{2}=6k^{2}-4kp+9kp-6p^{2}$
$=\left(-6p^{2}-4kp\right)+\left(9kp+6k^{2}\right)$
$=-2p(3p+2k)+3k(3p+2k)$
$=(3p+2k)(-2p+3k)$
$=(2k+3p)(3k-2p)$
