Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 112

Answer

$(3a - 4)^2$

Work Step by Step

$(3a + 5)^2$ - 18(3a + 5) + 81 $(3a + 5)^2$ - 2 * 9 * (3a + 5) + $9^2$ Now, $A^2$ - 2AB + $B^2$ = $(A-B)^2$ and A = 3a+5 , B = 9 Which implies, = $((3a+5) - 9)^2$ = $(3a - 4)^2$ which is the answer
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