Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 85

Answer

$\left( 3a-7\right) ^{2}$

Work Step by Step

$g\left( a-4\right) ^{2}+30\left( a-4\right) +25=\left( 3\left( a-4\right) \right) ^{2}+2\times \left( 3\left( a-4\right) \right) \times 5+5^{2}=\left( 3\left( a-4\right) +5\right) ^{2}=\left( 3a-7\right) ^{2}$
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