Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 89

Answer

$3\left( x+3\right) \left( 9x^{2}+25x+21\right) $

Work Step by Step

$\left( 3x+4\right) ^{3}-1=\left( 3x+4\right) ^{3}-1^{3}=\left( 3x+4-1\right) \left( \left( 3x+4\right) ^{2}+1\times \left( 3x+4\right) +1^{2}\right) =3\left( x+3\right) \left( 9x^{2}+25x+21\right) $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.