Answer
We can't further factor this trinomial.
Work Step by Step
When factoring $ax^{2}+bx+c$, we search for factors of $ac$ whose sum is $b,$
and, if we find them, we rewrite $bx$ and proceed to factor in groups.
Here, factors of $15\times 8=120$ that add to $24$ are .... we can't find such a pair.
$20\times 6$ add to $26,$
$15\times 8$ add to 23, etc.
No two add to 24.
We can't further factor this trinomial.
