Answer
$x=-1\pm\dfrac{2}{3}\sqrt{6}$
Work Step by Step
$3x^{2}+6x-5=0$
Use the quadratic formula to solve this equation. This formula is:
$x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
For this particular equation, $a=3$, $b=6$ and $c=-5$
$x=\dfrac{-6\pm\sqrt{(6)^{2}-4(3)(-5)}}{2(3)}=\dfrac{-6\pm\sqrt{36+60}}{6}=\dfrac{-6\pm\sqrt{96}}{6}$
$x=\dfrac{-6\pm4\sqrt{6}}{6}=-1\pm\dfrac{2}{3}\sqrt{6}$
