Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 57: 94

Answer

$x=\dfrac{5}{4}$

Work Step by Step

$\sqrt{8x-1}=3$ Let's square both sides of the equation: $(\sqrt{8x-1})^{2}=3^{2}$ $8x-1=9$ Solve for $x$: $8x=10$ $x=\dfrac{10}{8}=\dfrac{5}{4}$
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