Answer
$x=7$
Work Step by Step
$5=\sqrt{4x-3}$
Let's square both sides of the equation:
$5^{2}=(\sqrt{4x-3})^{2}$
$25=4x-3$
Solve for $x$:
$4x=28$
$x=\dfrac{28}{4}$
$x=7$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 57: 93
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