Answer
$x = -\frac{2}{3}$
Work Step by Step
$Find$ $all$ $real$ $solutions$ $of$ $the$ $quadratic$ $equation:$
$9x^2+12x+4= 0$
Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$
$9x^2+12x+4$
$a = 9, b = 12, c = 4$
$x = \frac{-(12) \pm \sqrt {(12)^2- 4(9 \times 4)}}{2(9)}$
$x = \frac{-12 \pm \sqrt {144- 144}}{18}$
$x = \frac{-12 \pm \sqrt {0}}{18}$
$x = \frac{-12}{18}$
$x = -\frac{2}{3}$
