Answer
$(a) 10.2\frac{in }{min}× \frac{1 min}{60 sec }× \frac{2.54 cm}{in}× \frac {10 mm}{cm}=4.318 \frac{mm}{sec} $
(b)$ 4.81 slugs×14.59 \frac{kg}{slugs}=70.1779 kg $
(c) $3.02 Ib×4.44 \frac{N}{Ib}=13.4 N$
(d) $0.0320 \frac{N.m}{sec}×\frac{Ib}{4.45 N}×3.28 \frac{ft}{m}=0.0236 \frac{Ib.ft}{sec}$
(e) $5.67 \frac{mm}{hr}×\frac{hr}{60 min}×\frac{min}{60 sec}×\frac{m}{10^{3}mm}×3.28 \frac{ft}{m}=0.0052 \times 10^{-3} \frac{ft}{sec}$
Work Step by Step
where conversions are as follows :
in = 2.54 cm
slugs = 14.59 kg
Ib = 4.45 N
meter = 3.28 ft
hr = 60 min
We put the corresponding value of each unit of BG unit to the equivalent in SI unit tn in the equation and delete the similarities we get the required value
