Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version 8th Edition

Published by Wiley
ISBN 10: 1119080703
ISBN 13: 978-1-11908-070-1

Chapter 1 - Problems - Page 32: 1.21

Answer

Convert quantities from SI unit to BG unit as follows : (a) $14.2 km×10^{3}\frac{m}{km}×3.28 \frac{ft}{m}= 46.6×10^{3}ft$ (b)$ 8.14 \frac{N}{m^{3}}×\frac{Ib}{4.45N}×\frac{m^{3}}{3.28^{3}ft^{3}} = 0.0518 \frac{Ib}{ft^{3}}$ (c) $1.61 \frac{kg}{m^{3}}×\frac{slug}{14.593 Kg}×\frac{m^{3}}{3.28^{3} ft^{3}} = 0.00312 \frac{slug}{ft^{3}}$ (d) $ 0.032\frac{N.m}{sec}×\frac{Ib}{4.45 N}×3.28 \frac{ft}{m}= 0.0236 \frac{Ib.ft }{sec} $ (e) $ 5.67 \frac{mm}{hr}×\frac{hr}{3600 sec}×\frac{m}{10^{3}mm}×3.28 \frac{ft}{m} = 0.52×10^{-5} \frac{ft}{sec}$

Work Step by Step

In order to convert from SI unit to BG unit, we put the equivalent quantities in each equation as follows : km = 1000 m m = 3.28 ft N = 4.45 Ib kg = 1 / 14.593 slugs hr = 3600 sec
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