Answer
Specific weight of liquid, $v=11281.5 \mathrm{~N} / \mathrm{m}^{3}$
Work Step by Step
Specific gravity of a given liquid, $S G=1.15$
We know that,
$S G=\frac{\text { Density of liquid }}{\text { Density of water }}$
Density of liquid $=S G \times($ Density of water in $\mathrm{S} . \mathrm{I}$ units $)$
Density of liquid, $\rho=1.15 \times 1000$
$\rho=1150 \mathrm{~kg} / \mathrm{m}^{3}$
Specific weight of liquid $=l \times g$
$v=1150 \times 9.81$
Specific weight of liquid, $v=11281.5 \mathrm{~N} / \mathrm{m}^{3}$
