Answer
$\frac{y+9}{y-1}$; $y \ne 1, 2$
Work Step by Step
To begin with, we will need to factor the numerator and the denominator:
$\frac{(y+9)(y-2)}{(y-1)(y-2)}$
Here, we can see that the $x - 2$ factors cancel out. As a result, we are left with $\frac{y+9}{y-1}$. This still will only hold true as long as we include our domain restrictions from earlier. This means that we must set the original denominator equal to 0:
$(y - 1)(y - 2) = 0$
This means, that $y = 1$ and $y = 2$ are both domain restrictions.
