Answer
$\frac{x-7}{x+7}$; $x\ne-7, 7$
Work Step by Step
To begin with, we will need to factor the numerator and the denominator. The numerator is a perfect square trinomial and the denominator is a difference of squares.
$\frac{(x-7)(x-7)}{(x+7)(x-7)}$
Here, we can see that the x-7 factors cancel out. As a result, we are left with $\frac{x-7}{x+7}$. This still will only hold true as long as we include our domain restrictions from earlier. This means that we must set the original denominator equal to 0:
$(x+7)(x−7)=0$
This means that $x=-7$ and $x=7$ are both domain restrictions.
