Answer
$ 1 ; x \ne 2,-2,-3,-5$
Work Step by Step
Factor each expression in the denominator and the numerator. We get
$=\frac{(x+2)(x-2)}{(x-2)(x+5)} \div \frac{(x+3)(x+2)}{(x+5)(x+3)} ; x \ne 2,-2,-3,-5;$
To divide, invert the divisor and then multiply.
$=\frac{(x+2)(x-2)}{(x-2)(x+5)} \times \frac{(x+5)(x+3)}{(x+3)(x+2)} ; x \ne 2,-2,-3,-5;$
Divide common factors. The result is
$ = 1 ; x \ne 2,-2,-3,-5$
