Answer
$\frac{y-5}{y+4}$; $y \ne -4, -1$
Work Step by Step
$\frac{y-5}{y+4}$; $y \ne -4, -1$
To begin with, we will need to factor the numerator and the denominator:
$\frac{(y+1)(y-5)}{(y+1)(y+4)}$
Here, we can see that the $x + 1$ factors cancel out. As a result, we are left with $\frac{y-5}{y+4}$. This still will only hold true as long as we include our domain restrictions from earlier. This means that we must set the original denominator equal to 0:
$(y + 1)(y + 4) = 0$
This means, that $y = -1$ and $y = -4$ are both domain restrictions.
